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2.4x^2-13.1x+2.2=0
a = 2.4; b = -13.1; c = +2.2;
Δ = b2-4ac
Δ = -13.12-4·2.4·2.2
Δ = 150.49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13.1)-\sqrt{150.49}}{2*2.4}=\frac{13.1-\sqrt{150.49}}{4.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13.1)+\sqrt{150.49}}{2*2.4}=\frac{13.1+\sqrt{150.49}}{4.8} $
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